SAT

Linear Inequalities Two Variables

🎯 What You'll Learn in This Lesson

  • What it means to graph an inequality in two variables.
  • When to use a solid versus dashed boundary line.
  • How to choose which side of the line to shade.
  • How to solve a SYSTEM of two-variable inequalities (the overlap region).
  • Speed tricks for matching graphs to systems.
  • 10 trick-based practice questions.

1. What Is a Two-Variable Inequality?

An equation in two variables (like y = 2x + 1) graphs as a single line. An INEQUALITY in two variables (like y β‰₯ 2x + 1) graphs as an entire REGION β€” the line plus everything on one side of it.

2. Three Steps to Graph

STEP 1 β€” Pretend the inequality is an equation. Graph the boundary line.

STEP 2 β€” SOLID line for ≀ or β‰₯. DASHED line for < or >.

STEP 3 β€” Shade the side that satisfies the inequality (use a test point).

3. The Test Point Trick

Pick any point NOT on the line β€” (0, 0) is usually easiest. Plug it into the original inequality. If the result is TRUE, shade the side containing that point. If FALSE, shade the OTHER side.

πŸ“ Example: Graph y > 2x βˆ’ 1

Boundary: y = 2x βˆ’ 1, slope 2, y-intercept βˆ’1.

Style: Strict > β†’ DASHED line.

Test (0, 0): 0 > 2(0) βˆ’ 1 β†’ 0 > βˆ’1 βœ“ TRUE. Shade the side containing the origin (above the line).

4. Solid vs. Dashed β€” At a Glance

❓ Does the inequality include the boundary?

≀ or β‰₯ β–Ό

< or > β–Ό

SOLID line (boundary is part of solution)

DASHED line (boundary is NOT included)

5. Systems of Two-Variable Inequalities

Two inequalities graphed together create an OVERLAP region. Any (x, y) point inside the overlap satisfies both inequalities at once.

πŸ’‘ Identifying the Overlap Region

Shade each inequality lightly with a different color or pattern. The DARKER region (where colors layer) is your solution set.

6. Speed Tricks

⚑ TRICK 1 β€” Solve for y first

Convert each inequality to y ≀ … or y β‰₯ … form. Then 'y β‰₯' means shade ABOVE; 'y ≀' means shade BELOW. Done in 5 seconds.

⚑ TRICK 2 β€” Origin test

If the boundary doesn't pass through (0, 0), use (0, 0) as your test point. Plug it in: if true, shade the half-plane containing the origin; if false, the other half.

⚑ TRICK 3 β€” Spot dashed vs. solid in answer choices

On graph-matching multiple-choice questions, the line style (solid/dashed) usually differs across choices. Knock out half the options instantly by checking the inequality symbol.

⚠️ Watch Out!

  • Drawing a dashed line for ≀ or β‰₯, or a solid line for < or >.
  • Shading the wrong side because of an arithmetic slip in the test point.
  • Forgetting to check that test point is NOT on the boundary line.
  • When solving for y, forgetting to flip the inequality if you divided by a negative.

7. Summary

πŸ“Œ The Whole Topic in 30 Seconds

  • Boundary line: Solid for ≀ or β‰₯; dashed for < or >.
  • Shade: Use a test point. (0, 0) is the easiest if not on the line.
  • y β‰₯ form: Shade above the line.
  • y ≀ form: Shade below the line.
  • System: Solution is the overlap of all shaded regions.

8. Practice β€” 10 Questions

Q1. Which point is a solution to y < 2x + 1?

A) (0, 5) B) (1, 0) C) (2, 6) D) (3, 8)

Hint: Plug each in. (1, 0): 0 < 3 βœ“

Q2. The boundary line of y β‰₯ 3x βˆ’ 2 is drawn how?

A) Dashed B) Solid C) Dotted D) None

Hint: β‰₯ includes the boundary β†’ solid.

Q3. Which inequality is satisfied by (0, 0)?

A) y > 2x + 5 B) y ≀ x βˆ’ 3 C) y < βˆ’x + 1 D) y β‰₯ 4x + 2

Hint: Plug (0,0): only C gives 0 < 1 βœ“

Q4. The graph of y < x has what features?

A) Solid line, shaded above B) Solid line, shaded below C) Dashed line, shaded above D) Dashed line, shaded below

Hint: <: dashed. y < x: shade below.

Q5. Which of the following is NOT a solution to y β‰₯ βˆ’x + 4?

A) (0, 4) B) (5, 5) C) (1, 0) D) (3, 2)

Hint: (1, 0): 0 β‰₯ 3 is false.

Q6. A system: y > x and y < βˆ’x + 6. Which point is in the overlap?

A) (0, 0) B) (4, 1) C) (1, 2) D) (3, 5)

Hint: (1, 2): 2 > 1 βœ“ and 2 < 5 βœ“

Q7. The boundary of y > 2 is drawn how?

A) Solid horizontal line at y = 2, shaded above B) Dashed horizontal line at y = 2, shaded above C) Dashed vertical line D) Solid vertical line

Hint: y > 2: dashed horizontal, shade above.

Q8. Which inequality describes 'shade below the line y = (1/2)x + 3, boundary included'?

A) y < (1/2)x + 3 B) y ≀ (1/2)x + 3 C) y > (1/2)x + 3 D) y β‰₯ (1/2)x + 3

Hint: 'Below' = ≀ (boundary included).

Q9. Which point satisfies BOTH 2x + y ≀ 6 AND x βˆ’ y β‰₯ 0?

A) (0, 6) B) (3, 0) C) (1, 5) D) (4, 4)

Hint: (3, 0): 6 ≀ 6 βœ“ and 3 β‰₯ 0 βœ“

Q10. The line y = βˆ’x + 4 is dashed and shaded above. Which inequality matches?

A) y < βˆ’x + 4 B) y > βˆ’x + 4 C) y ≀ βˆ’x + 4 D) y β‰₯ βˆ’x + 4

Hint: Dashed β†’ strict; shaded above β†’ >.

Answer Key & Shortcut Solutions

#

Answer

Shortcut Reason

Q1.

B) (1, 0)

Plug into y < 2x + 1: 0 < 3 βœ“

Q2.

B) Solid

β‰₯ β†’ boundary included β†’ solid line.

Q3.

C) y < βˆ’x + 1

Origin: 0 < 1 βœ“

Q4.

D) Dashed, below

< β†’ dashed; y < x β†’ below.

Q5.

C) (1, 0)

0 β‰₯ 3 is false.

Q6.

C) (1, 2)

Both 2 > 1 and 2 < 5 hold.

Q7.

B) Dashed, above

y > 2: dashed horizontal, shade above.

Q8.

B) y ≀ (1/2)x + 3

Below + included = ≀

Q9.

B) (3, 0)

Satisfies both.

Q10.

B) y > βˆ’x + 4

Strict + above = >

πŸš€ You've Got This! πŸ’ͺ

Two-variable inequalities are just one-variable inequalities… in 2D! Master test-point shading and you're set.

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